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📅 May 15, 2026 👤 scraface

May 15, 2026

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Subtract: \( (2u^3 - 2u^2 + 0u) - (2u^3 - 4u^2 + 4u) = 2u^2 - 4u \)
Now: \( 2u^2 \div u^2 = 2 \), multiply: \( 2(u^2 - 2u + 2) = 2u^2 - 4u...
Subtract: \( (2u^2 - 4u + 3) - (2u^2 - 4u + 4) = -1 \)
So remainder is \( -1 \)
oxed{-1}
Solve the inequality \( rac{2x - 1}{x + 3} > 1 \), where \( x
eq -3 \).
We solve:
rac{2x - 1}{x + 3} > 1
Subtract 1 from both sides:

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