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📅 May 16, 2026 👤 scraface

May 16, 2026

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n \equiv 0 \pmod{36}, \quad n \equiv 3 \pmod{7}
We solve this system using the Chinese Remainder Theorem. Since 36 and...
Let’s find $n$ such that:
Let $n = 36k$. Then:
36k \equiv 3 \pmod{7} \Rightarrow k \equiv 3 \cdot 36^{-1} \pmod{7}
Since $36 \equiv 1 \pmod{7}$, its inverse modulo 7 is 1. So:
k \equiv 3 \pmod{7} \Rightarrow k = 7m + 3
Then $n = 36k = 36(7m + 3) = 252m + 108$.
We seek the smallest four-digit value of $n$:
252m + 108 \geq 1000 \Rightarrow 252m \geq 892 \Rightarrow m \geq \lef...

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