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📅 May 14, 2026 👤 scraface

May 14, 2026

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Multiply \( 3t \) by \( t + 1 \): \( 3t^2 + 3t \).
Subtract: \( (3t^2 + 2t + 1) - (3t^2 + 3t) = -t + 1 \).
Divide \( -t \) by \( t \) to get \(-1\).
Multiply: \(-1(t + 1) = -t - 1\).
Subtract: \( (-t + 1) - (-t - 1) = 2 \).
\[ G(t) = 3t - 1 + \frac{2}{t + 1} \]
As \( t \to \infty \), the term \( \frac{2}{t + 1} \to 0 \), so:
\[ G(t) \to 3t - 1 \]
This grows without bound, so there is no horizontal asymptote.
However, the **slant asymptote** is the line \( y = 3t - 1 \), but sin...

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