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v(v - 2)(v - 3) = 0. - Professionaloutdoormedia

📅 May 14, 2026 👤 scraface

May 14, 2026

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3t^2 - 4t + 1 = 0
Solve this quadratic equation using the quadratic formula:
where \(a = 3\), \(b = -4\), and \(c = 1\). Substituting:
t = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 3 \cdot 1}}{2 \cdot 3}
t = \frac{4 \pm \sqrt{16 - 12}}{6}
t = \frac{4 \pm \sqrt{4}}{6}
t = \frac{4 \pm 2}{6}
t = \frac{6}{6} = 1 \quad \text{and} \quad t = \frac{2}{6} = \frac{1}{...
Both values satisfy the equation. Thus, the values of \(t\) are:
\boxed{1 \quad \text{and} \quad \frac{1}{3}}

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