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Home » Thus, the possible answers are $ \boxed43 $ and $ \boxed78 $. - Professionaloutdoormedia

Thus, the possible answers are $ \boxed43 $ and $ \boxed78 $. - Professionaloutdoormedia

📅 May 15, 2026 👤 scraface

May 15, 2026

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📌 \boxed{\dfrac{2}{3}}

📌 Question: A drug dosage model requires solving $ \log_2(x + 4) - \log_2(x - 1) = 3 $. Find the value of $ x $.

📌 Solution: Combine logs: $ \log_2\left(\frac{x + 4}{x - 1}\right) = 3 $. Rewrite in exponential form: $ \frac{x + 4}{x - 1} = 2^3 = 8 $. Solve: $ x + 4 = 8x - 8 \Rightarrow -7x = -12 \Rightarrow x = \frac{12}{7} $. Verify $ x > 1 $ to ensure validity.

📌 \boxed{\dfrac{12}{7}}Question: Find all angles $ \theta \in [0^\circ, 360^\circ] $ that satisfy $ 2\cos(2\theta) + 1 = 0 $, inspired by periodic patterns in environmental data trends.

📌 Solution: Start by solving $ 2\cos(2\theta) + 1 = 0 \Rightarrow \cos(2\theta) = -\frac{1}{2} $. The general solutions for $ 2\theta $ are $ 2\theta = 120^\circ + 360^\circ k $ or $ 2\theta = 240^\circ + 360^\circ k $, where $ k \in \mathbb{Z} $. Dividing by 2, $ \theta = 60^\circ + 180^\circ k $ or $ \theta = 120^\circ + 180^\circ k $. For $ \theta \in [0^\circ, 360^\circ] $, the solutions are $ 60^\circ, 120^\circ, 240^\circ, 300^\circ $.

📌 \boxed{60^\circ, 120^\circ, 240^\circ, 300^\circ}

📌 Question: Let $ z^4 + z^2 + 1 = 0 $. Express the maximum imaginary part of a root as $ \sin \theta $, where $ \theta \in [0^\circ, 360^\circ] $, reflecting harmonic analysis in linguistic frequency models.

📌 Solution: Factor $ z^4 + z^2 + 1 = (z^2 + z + 1)(z^2 - z + 1) = 0 $. Solving $ z^2 + z + 1 = 0 $ gives roots $ z = \frac{-1 \pm i\sqrt{3}}{2} $, with imaginary parts $ \pm \frac{\sqrt{3}}{2} $. Solving $ z^2 - z + 1 = 0 $ gives $ z = \frac{1 \pm i\sqrt{3}}{2} $, with imaginary parts $ \pm \frac{\sqrt{3}}{2} $. The maximum imaginary part is $ \frac{\sqrt{3}}{2} = \sin 60^\circ $.

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