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📅 May 14, 2026 👤 scraface

May 14, 2026

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Since the divisor is quadratic, the remainder is linear: $ R(x) = ax +...
f(a + b + c) = f(a) + f(b) + f(c) - 3f(abc)
We now know $ f(a + b) = f(a) + f(b) $ for all $ a,b $. So $ f $ is ad...
Now return to original equation (since $ f(0) = 0 $ and additivity is...
But $ f(a + b + c) = f(a) + f(b) + f(c) $, so:
So the only solution is the zero function.
Hence, only one such function exists.
Solution: First, simplify the left-hand side:
But we must consider the domain: $ x
e 1 $. Throughout, the expression is undefined at $ x = 1 $, and the i...

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