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\[ 11h = 27 \]
Divide by 11:
\[ h = \frac{27}{11} \]
Now substitute \( h = \frac{27}{11} \) back into \( k = 2h - 4 \):
\[ k = 2\left(\frac{27}{11}\right) - 4 \]
\[ k = \frac{54}{11} - \frac{44}{11} \]
\[ k = \frac{10}{11} \]
Thus, the energy values are:
\[ \boxed{h = \frac{27}{11}, \, k = \frac{10}{11}} \]
Question:** A marine autonomous underwater geological mapping engineer...

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