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Home » Final Clarified Question (if LCM allowed): - Professionaloutdoormedia

Final Clarified Question (if LCM allowed): - Professionaloutdoormedia

📅 May 14, 2026 👤 scraface

May 14, 2026

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From second equation: \(z = 3x\)
From first: \(3y = 2z = 2(3x) = 6x \Rightarrow y = 2x\)
Substitute into third:
2x - (2x) = 5 \Rightarrow 0 = 5
Contradiction! So no solution exists unless the cross product is ortho...
e 0\), so inherently inconsistent.
But wait: the cross product must be perpendicular to \(\mathbf{a}\). C...
egin{pmatrix} 0 \ 0 \ 5 \end{pmatrix} \cdot egin{pmatrix} 1 \ 2 \ 3...
So no such \(\mathbf{v}\) exists because the given vector is not perpe...
However, if we assume a typo and the right-hand side is perpendicular,...

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