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📅 May 15, 2026 👤 scraface

May 15, 2026

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x + y = a \quad \text{و} \quad y + z = a
نعوض $y = a - x$ في $y + z = a$:
a - x + z = a \quad \Rightarrow \quad z = x
نعوض $z = x$ و $y = a - x$ في $x^2 + y^2 + z^2 = 2a^2$:
x^2 + (a - x)^2 + x^2 = 2a^2 \quad \Rightarrow \quad x^2 + a^2 - 2ax +...
x = \frac{2a \pm \sqrt{4a^2 + 12a^2}}{6} = \frac{2a \pm 4a}{6} \quad \...
بما أن $x$ يجب أن يكون عددًا صحيحًا، فإن $x = a$، وبالتالي $y = 0$ و $...
\boxed{(a, 0, a)}
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