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Home » But earlier calculation with recurrence gave \(a_5 = 13\), yes. - Professionaloutdoormedia

But earlier calculation with recurrence gave \(a_5 = 13\), yes. - Professionaloutdoormedia

📅 May 15, 2026 👤 scraface

May 15, 2026

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\[ 3p = 2q + 8 \]
\[ p = \frac{2q + 8}{3} \]
Substitute \( p = \frac{2q + 8}{3} \) into the first equation:
\[ 7\left(\frac{2q + 8}{3}\right) + 5q = 35 \]
Multiply through by 3 to clear the fraction:
\[ 7(2q + 8) + 15q = 105 \]
Expand and simplify:
\[ 14q + 56 + 15q = 105 \]
\[ 29q + 56 = 105 \]
Subtract 56 from both sides:

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