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Home » Alanis & The Zombie Hunters: Natures Deadliest Night Hunters Exposed! - Professionaloutdoormedia

Alanis & The Zombie Hunters: Natures Deadliest Night Hunters Exposed! - Professionaloutdoormedia

📅 May 16, 2026 👤 scraface

May 16, 2026

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📌 Prüfe Vorzeichenwechsel: \( f(0) = -18 < 0 \), \( f(1) = 1 - 8 + 9 - 18 = -16 < 0 \), \( f(2) = 8 - 32 + 18 - 18 = -24 < 0 \), \( f(3) = 27 - 72 + 27 - 18 = -36 < 0 \), \( f(4) = 64 - 128 + 36 - 18 = -46 < 0 \), \( f(5) = -48 < 0 \), \( f(6) = -36 < 0 \), \( f(6.7) \approx 302.5 - 360.88 + 60.3 - 18 \approx -16.08 \), \( f(6.9) \approx 328.5 - 383.28 + 62.1 - 18 \approx -0.68 \), \( f(6.95) \approx 334.5 - 388.18 + 62.55 - 18 \approx 0.87 > 0 \).

📌 Also eine reelle Wurzel zwischen 6.9 und 6.95, und da es nur eine reelle Wurzel ist (nach Ableitung und Graphie-Analyse), und zwei komplexe, dann gibt es nur **eine** reelle \( w \), also nur **eine** reelle \( v \).

📌 Aber das widerspricht der Annahme „alle Wurzeln sind reell. Da die Gleichung kubisch ist, müssen entweder drei reelle oder eine reelle und zwei komplexe sein.

📌 Wir müssen prüfen, ob alle Wurzeln \( w_i \) reell sind. Diskriminante eines Kubus \( w^3 + pw + q \): erste Form für \( w^3 + aw^2 + bw + c \), hier:

📌 \( f(w) = w^3 - 8w^2 + 9w - 18 \), also ohne \( w^2 \) bei Transformation? Besser: mache Substitution \( w = z + \frac{8}{3} \).

📌 Sei \( w = z + \frac{8}{3} \), dann:

📌 f(z) = \left(z + \frac{8}{3}\right)^3 - 8\left(z + \frac{8}{3}\right)^2 + 9\left(z + \frac{8}{3}\right) - 18.

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